consider the following reaction.\nco₂(g) + h₂(g) → co(g) + h₂o(l)\nwhat is being oxidized?\ncarbon\ncarbon…

Explanation:

Step1: Determine oxidation numbers

Oxidation number of C in $CO_2$: Let oxidation number of C be $x$. Oxygen has an oxidation - number of - 2. In $CO_2$, $x+2\times(-2)=0$, so $x = + 4$. In CO, let oxidation number of C be $y$. Then $y+( - 2)=0$, so $y = + 2$. Oxidation number of H in $H_2$ is 0. In $H_2O$, oxidation number of H is + 1.

Step2: Identify the oxidized species

Oxidation is the increase in oxidation number. Hydrogen goes from an oxidation number of 0 in $H_2$ to + 1 in $H_2O$.

Answer:

hydrogen