consider the following reversible reaction.\nco(g) + 2h₂(g) ⇌ ch₃oh(g)\nwhat is the equilibrium constant…

consider the following reversible reaction.\nco(g) + 2h₂(g) ⇌ ch₃oh(g)\nwhat is the equilibrium constant expression for the given system?\n○ keq = coh2²/ch₃oh\n○ keq = ch₃oh/coh2²\n○ keq = coh2/ch₃oh\n○ keq = ch₃oh/coh2

consider the following reversible reaction.\nco(g) + 2h₂(g) ⇌ ch₃oh(g)\nwhat is the equilibrium constant expression for the given system?\n○ keq = coh2²/ch₃oh\n○ keq = ch₃oh/coh2²\n○ keq = coh2/ch₃oh\n○ keq = ch₃oh/coh2

Answer

Explanation:

Step1: Recall equilibrium constant formula

For a general reaction $aA + bB\rightleftharpoons cC + dD$, the equilibrium - constant expression $K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$, where $[ ]$ represents the molar concentration of the species and the exponents are the coefficients from the balanced chemical equation.

Step2: Identify reactants and products and their coefficients

In the reaction $CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)$, the reactants are $CO$ and $H_2$ with coefficients 1 and 2 respectively, and the product is $CH_3OH$ with coefficient 1.

Step3: Write the equilibrium - constant expression

$K_{eq}=\frac{[CH_3OH]}{[CO][H_2]^2}$

Answer:

$K_{eq}=\frac{[CH_3OH]}{[CO][H_2]^2}$