consider the half reactions below for a chemical reaction. mg→mg²⁺(aq)+2e⁻ 2h⁺(aq)+2e⁻→h₂(g) what is the…

consider the half reactions below for a chemical reaction. mg→mg²⁺(aq)+2e⁻ 2h⁺(aq)+2e⁻→h₂(g) what is the overall equation for this chemical reaction? o mg(s)+2h⁺(aq)→mg²⁺(aq)+h₂(g) o mg(s)+2h⁺(aq)→mg²⁺(aq)+2e⁻ o mg²⁺(aq)+h₂(g)→mg(s)+2h⁺(aq) o mg(s)+2h→mg(aq)+h₂(g)

consider the half reactions below for a chemical reaction. mg→mg²⁺(aq)+2e⁻ 2h⁺(aq)+2e⁻→h₂(g) what is the overall equation for this chemical reaction? o mg(s)+2h⁺(aq)→mg²⁺(aq)+h₂(g) o mg(s)+2h⁺(aq)→mg²⁺(aq)+2e⁻ o mg²⁺(aq)+h₂(g)→mg(s)+2h⁺(aq) o mg(s)+2h→mg(aq)+h₂(g)

Answer

Answer:

A. $\text{Mg}(s)+2\text{H}^+(aq)\longrightarrow\text{Mg}^{2 +}(aq)+\text{H}_2(g)$

Explanation:

Step1: Identify half - reactions

Oxidation: $\text{Mg}\longrightarrow\text{Mg}^{2+}(aq)+2\text{e}^-$ Reduction: $2\text{H}^+(aq)+2\text{e}^-\longrightarrow\text{H}_2(g)$

Step2: Combine half - reactions

Add the two half - reactions. The electrons cancel out. $\text{Mg}+2\text{H}^+(aq)+2\text{e}^-\longrightarrow\text{Mg}^{2+}(aq)+2\text{e}^-+\text{H}_2(g)$ After canceling electrons, we get $\text{Mg}(s)+2\text{H}^+(aq)\longrightarrow\text{Mg}^{2 +}(aq)+\text{H}_2(g)$