consider the nuclear equation below.\n$x\\longrightarrow_{89}^{228}ac +_{-1}^{0}\\beta$\nwhat is the nuclide…

consider the nuclear equation below.\n$x\\longrightarrow_{89}^{228}ac +_{-1}^{0}\\beta$\nwhat is the nuclide symbol of x?\n$_{90}^{230}th$\n$_{89}^{229}ac$\n$_{90}^{228}th$\n$_{88}^{228}ra$

consider the nuclear equation below.\n$x\\longrightarrow_{89}^{228}ac +_{-1}^{0}\\beta$\nwhat is the nuclide symbol of x?\n$_{90}^{230}th$\n$_{89}^{229}ac$\n$_{90}^{228}th$\n$_{88}^{228}ra$

Answer

Explanation:

Step1: Apply mass - number conservation

In a nuclear equation, the sum of mass - numbers on the left side equals the sum on the right side. The mass - number of $^{228}{89}Ac$ is 228 and of $^{\ \ 0}{- 1}\beta$ is 0. Let the mass - number of $X$ be $A$. Then $A=228 + 0=228$.

Step2: Apply atomic - number conservation

The sum of atomic numbers on the left side equals the sum on the right side. The atomic number of $^{228}{89}Ac$ is 89 and of $^{\ \ 0}{- 1}\beta$ is - 1. Let the atomic number of $X$ be $Z$. Then $Z=89+( - 1)=90$.

Step3: Identify the element

The element with atomic number $Z = 90$ is thorium (Th).

Answer:

$^{228}_{90}Th$