consider the reaction below.\n2al₂o₃ → 4al + 3o₂\nhow many moles of oxygen are produced when 26.5 mol of…

consider the reaction below.\n2al₂o₃ → 4al + 3o₂\nhow many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed?\no 17.7 mol\no 19.9 mol\no 39.8 mol\no 53.0 mol

consider the reaction below.\n2al₂o₃ → 4al + 3o₂\nhow many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed?\no 17.7 mol\no 19.9 mol\no 39.8 mol\no 53.0 mol

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $2Al_2O_3\rightarrow4Al + 3O_2$, the mole - ratio of $Al_2O_3$ to $O_2$ is $2:3$.

Step2: Set up proportion

Let $x$ be the number of moles of $O_2$ produced. We have the proportion $\frac{2}{3}=\frac{26.5}{x}$.

Step3: Solve for $x$

Cross - multiply: $2x = 3\times26.5$. Then $x=\frac{3\times26.5}{2}=\frac{79.5}{2}=39.75\approx39.8$ mol.

Answer:

39.8 mol