consider the reaction below.\nna⁺ + c₂h₃o₂⁻(aq) + h⁺ + cl⁻ → na⁺ + cl⁻ + hc₂h₃o₂\nwhich is the net ionic…

consider the reaction below.\nna⁺ + c₂h₃o₂⁻(aq) + h⁺ + cl⁻ → na⁺ + cl⁻ + hc₂h₃o₂\nwhich is the net ionic equation for the reaction?\nh⁺ + cl⁻ → hcl\nna⁺ + cl⁻ → nacl\nna⁺ + c₂h₃o₂⁻ → nac₂h₃o₂\nc₂h₃o₂⁻(aq) + h⁺ → hc₂h₃o₂

consider the reaction below.\nna⁺ + c₂h₃o₂⁻(aq) + h⁺ + cl⁻ → na⁺ + cl⁻ + hc₂h₃o₂\nwhich is the net ionic equation for the reaction?\nh⁺ + cl⁻ → hcl\nna⁺ + cl⁻ → nacl\nna⁺ + c₂h₃o₂⁻ → nac₂h₃o₂\nc₂h₃o₂⁻(aq) + h⁺ → hc₂h₃o₂

Answer

Explanation:

Step1: Identify spectator ions

Spectator ions are those that appear on both sides of the total ionic equation and do not participate in the actual reaction. In the given reaction $Na^+(aq)+C_2H_3O_2^-(aq)+H^+(aq)+Cl^-(aq)\longrightarrow Na^+(aq)+Cl^-(aq)+HC_2H_3O_2$, $Na^+$ and $Cl^-$ are spectator ions.

Step2: Write net - ionic equation

Remove the spectator ions from the total ionic equation. After removing $Na^+$ and $Cl^-$ from both sides, we get $C_2H_3O_2^-(aq)+H^+(aq)\longrightarrow HC_2H_3O_2$.

Answer:

$C_2H_3O_2^-(aq)+H^+\longrightarrow HC_2H_3O_2$