consider the redox reaction below.\nag⁺(aq) + zn(s) → zn²⁺(aq) + ag(s)\nbalance the silver half - reaction…

Explanation:

Step1: Identify the silver half-reaction

The silver species in the reaction is ( \text{Ag}^+(aq) ) on the reactant side and ( \text{Ag}(s) ) on the product side. So the half - reaction for silver is ( \text{Ag}^+(aq)\to\text{Ag}(s) ).

Step2: Balance atoms

The number of silver atoms is already balanced (1 Ag on each side).

Step3: Balance charge

The charge on the left - hand side (LHS) is ( + 1) (from ( \text{Ag}^+ )) and on the right - hand side (RHS) is ( 0) (from ( \text{Ag}(s) )). To balance the charge, we need to add 1 electron to the left - hand side because electrons have a negative charge. The balanced half - reaction is ( \text{Ag}^+(aq)+e^-\to\text{Ag}(s) ). So the number of electrons transferred in the silver half - reaction is 1.

Answer:

1