count the number of atoms on each side of the chemical equations and label them as equal mass or unequal mass.
count the number of atoms on each side of the chemical equations and label them as equal mass or unequal mass.
Answer
Explanation:
Step1: Analyze $H_2 + O_2\rightarrow H_2O$
On the left - hand side, 2 H atoms and 2 O atoms. On the right - hand side, 2 H atoms and 1 O atom. So it's unequal mass.
Step2: Analyze $N_2+3H_2\rightarrow 2NH_3$
On the left - hand side, 2 N atoms and 6 H atoms. On the right - hand side, 2 N atoms and 6 H atoms. So it's equal mass.
Step3: Analyze $4P + 5O_2\rightarrow 2P_2O_5$
On the left - hand side, 4 P atoms and 10 O atoms. On the right - hand side, 4 P atoms and 10 O atoms. So it's equal mass.
Step4: Analyze $S_8+F_2\rightarrow SF_6$
On the left - hand side, 8 S atoms and 2 F atoms. On the right - hand side, 1 S atom and 6 F atoms. So it's unequal mass.
Answer:
$H_2 + O_2\rightarrow H_2O$: unequal mass $N_2+3H_2\rightarrow 2NH_3$: equal mass $4P + 5O_2\rightarrow 2P_2O_5$: equal mass $S_8+F_2\rightarrow SF_6$: unequal mass