counting atoms assessment\n1 fill in the blank 1 point\nif the chemical formula is 2ca₃(po₄)₂, how many…

counting atoms assessment\n1 fill in the blank 1 point\nif the chemical formula is 2ca₃(po₄)₂, how many total oxygen atoms are present?\ntype your answer...

counting atoms assessment\n1 fill in the blank 1 point\nif the chemical formula is 2ca₃(po₄)₂, how many total oxygen atoms are present?\ntype your answer...

Answer

Explanation:

Step1: Analyze the sub - script of oxygen in the formula

In the formula (Ca_3(PO_4)_2), the sub - script of (O) is (4).

Step2: Consider the coefficient outside the parentheses

The coefficient outside the ((PO_4)) group is (2). So the number of (O) atoms from one (Ca_3(PO_4)_2) unit is (4\times2 = 8).

Step3: Consider the coefficient in front of the entire formula

The coefficient in front of (Ca_3(PO_4)_2) is (2). So the total number of (O) atoms is (8\times2=16).

Answer:

(16)