the decomposition of dinitrogen tetroxide into nitrogen gas and oxygen gas is shown by which balanced…
the decomposition of dinitrogen tetroxide into nitrogen gas and oxygen gas is shown by which balanced chemical equation? a n₂(g) + 2o₂(g) → n₂o₄(g) b n₂o₄(g) → n₂(g) + o₂(g) c n₂o₄(g) → n₂(g) + 2o₂(g) d n₂o₄(g) + 2o₂(g) → n₂(g)
Answer
Explanation:
Step1: Analyze reactant and products
The reactant is dinitrogen tetroxide ($N_2O_4$) and products are nitrogen gas ($N_2$) and oxygen gas ($O_2$). The reaction is a decomposition, so $N_2O_4$ is on the left - hand side and $N_2$ and $O_2$ are on the right - hand side.
Step2: Balance the oxygen atoms
In $N_2O_4$, there are 4 oxygen atoms. On the product side, to balance the 4 oxygen atoms in $N_2O_4$, we need 2 moles of $O_2$ since each $O_2$ molecule has 2 oxygen atoms. The nitrogen atoms are already balanced as there are 2 nitrogen atoms in $N_2O_4$ and 2 nitrogen atoms in $N_2$. The balanced equation is $N_2O_4(g)\rightarrow N_2(g)+2O_2(g)$.
Answer:
C. $N_2O_4(g)\rightarrow N_2(g)+2O_2(g)$