determine the number of particles in the 2.20 mol sample of sio2. 1 mol sio2 = 6.02 x 10^23 particles sio2…

determine the number of particles in the 2.20 mol sample of sio2. 1 mol sio2 = 6.02 x 10^23 particles sio2 2.20 mol sio2 = ? x 10^? particles sio2 enter the coefficient in the green box and the exponent in the yellow box. round your coefficient to two decimal places.

determine the number of particles in the 2.20 mol sample of sio2. 1 mol sio2 = 6.02 x 10^23 particles sio2 2.20 mol sio2 = ? x 10^? particles sio2 enter the coefficient in the green box and the exponent in the yellow box. round your coefficient to two decimal places.

Answer

Answer:

1.32, 24

Explanation:

Step1: Set up the proportion

We know that 1 mol of $SiO_2$ has $6.02\times10^{23}$ particles. Let $x$ be the number of particles in 2.20 mol of $SiO_2$. The proportion is $\frac{1\ mol}{6.02\times10^{23}\ particles}=\frac{2.20\ mol}{x}$.

Step2: Solve for $x$

Cross - multiply: $x = 2.20\times6.02\times10^{23}$.

Step3: Calculate the result

$2.20\times6.02=13.244$. So $x = 13.244\times10^{23}$. In scientific notation, this is $1.3244\times 10^{24}$. Rounding the coefficient to two decimal places, we get $1.32\times10^{24}$. So the coefficient is 1.32 and the exponent is 24.