determine the number of particles in the 0.28 mol sample of babr2. 1 mol babr2 = 6.02 x 10^23 particles…

determine the number of particles in the 0.28 mol sample of babr2. 1 mol babr2 = 6.02 x 10^23 particles babr2 0.28 mol babr2 = ? x 10^? particles babr2 enter the coefficient in the green box and the exponent in the yellow box. round your coefficient to two decimal places.

determine the number of particles in the 0.28 mol sample of babr2. 1 mol babr2 = 6.02 x 10^23 particles babr2 0.28 mol babr2 = ? x 10^? particles babr2 enter the coefficient in the green box and the exponent in the yellow box. round your coefficient to two decimal places.

Answer

Explanation:

Step1: Use Avogadro's number relationship

We know that 1 mol of any substance contains $6.02\times 10^{23}$ particles. Let $N$ be the number of particles in 0.28 mol of $BaBr_2$. We use the proportion $\frac{N}{0.28\ mol}=\frac{6.02\times 10^{23}\ particles}{1\ mol}$.

Step2: Solve for the number of particles

$N = 0.28\ mol\times6.02\times 10^{23}\ particles/mol$. $N=(0.28\times6.02)\times 10^{23}$ particles. $0.28\times6.02 = 1.6856$. Rounding to two - decimal places, we get 1.69. So $N = 1.69\times 10^{23}$ particles.

Answer:

Coefficient in green box: 1.69 Exponent in yellow box: 23