determine the number of particles in the 1.95 mol sample of sf6.\n1 mol sf6 = 6.02×10²³ particles sf6\n1.95…

determine the number of particles in the 1.95 mol sample of sf6.\n1 mol sf6 = 6.02×10²³ particles sf6\n1.95 mol sf6 = ?×10^? particles sf6\nenter the coefficient in the green box and the exponent in the yellow box.\nround your coefficient to two decimal places.

determine the number of particles in the 1.95 mol sample of sf6.\n1 mol sf6 = 6.02×10²³ particles sf6\n1.95 mol sf6 = ?×10^? particles sf6\nenter the coefficient in the green box and the exponent in the yellow box.\nround your coefficient to two decimal places.

Answer

Answer:

Coefficient: 11.74, Exponent: 23

Explanation:

Step1: Set up the proportion

We know that 1 mol of $SF_6$ has $6.02\times 10^{23}$ particles. Let $x$ be the number of particles in 1.95 mol of $SF_6$. The proportion is $\frac{x}{1.95\ mol}=\frac{6.02\times 10^{23}\ particles}{1\ mol}$.

Step2: Solve for $x$

$x = 1.95\times6.02\times 10^{23}$ particles. Calculate $1.95\times6.02 = 11.739$. Rounding to two - decimal places, we get 11.74. So $x=11.74\times 10^{23}$ particles.