determine the number of protons in an isotope with 15 neutrons and with an atomic mass number of 49. (note…

determine the number of protons in an isotope with 15 neutrons and with an atomic mass number of 49. (note: this ion might not be physically realizable.) 49 15 34 64 10 numeric 10 points a nonmetal element was discovered and named ridlium, rm. what is the molecular weight of ridlium if the compound triridlium hexafluoride has a molecular weight of 344.673 amu? answer

determine the number of protons in an isotope with 15 neutrons and with an atomic mass number of 49. (note: this ion might not be physically realizable.) 49 15 34 64 10 numeric 10 points a nonmetal element was discovered and named ridlium, rm. what is the molecular weight of ridlium if the compound triridlium hexafluoride has a molecular weight of 344.673 amu? answer

Answer

Explanation:

Step1: Recall atomic mass formula

Atomic mass number = number of protons + number of neutrons.

Step2: Solve for number of protons

Let the number of protons be $p$. Given atomic mass number = 49 and number of neutrons = 15. So, $p=49 - 15$. $p = 34$

Answer:

34

Explanation for second - part:

Step1: Determine the formula for the compound

The formula for triridium hexafluoride is $Rr_3F_6$. The atomic weight of fluorine ($F$) is approximately 18.9984 amu. The molecular weight of $F_6$ is $6\times18.9984= 113.9904$ amu.

Step2: Solve for the atomic weight of ridlium

Let the atomic weight of ridlium be $x$. The molecular weight of $Rr_3F_6$ is $3x+113.9904$. Given the molecular weight of $Rr_3F_6$ is 344.673 amu. So, $3x+113.9904 = 344.673$. First, subtract 113.9904 from both sides: $3x=344.673 - 113.9904=230.6826$. Then divide both sides by 3: $x=\frac{230.6826}{3}=76.8942$ amu.

Answer:

76.8942