determine the ph of 0.050 m hno₃ solution. hno₃ is a strong acid.

Explanation:

Step1: Identify $H^+$ concentration

Since $HNO_3$ is a strong acid, it completely dissociates. So $[H^+]=[HNO_3]=0.050\ M$.

Step2: Calculate pH

The formula for pH is $pH = -\log[H^+]$. Substitute $[H^+]=0.050$ into the formula: $pH=-\log(0.050)$. $pH = 1.30$

Answer:

$1.30$