determine the quantity of moles of propylene (c₃h₆) in 25.0 g of the substance. 25.0 g c₃h₆×1 mol c₃h₆/42.09…

determine the quantity of moles of propylene (c₃h₆) in 25.0 g of the substance. 25.0 g c₃h₆×1 mol c₃h₆/42.09 g c₃h₆=
Answer
Explanation:
Step1: Identify molar - mass of propylene
The molar mass of propylene ($C_3H_6$) is calculated as follows: The atomic mass of $C$ is approximately $12.01\ g/mol$ and $H$ is approximately $1.01\ g/mol$. For $C_3H_6$, $M=(3\times12.01 + 6\times1.01)\ g/mol=42.09\ g/mol$.
Step2: Use the mole - mass formula
The formula to calculate the number of moles ($n$) is $n=\frac{m}{M}$, where $m$ is the mass and $M$ is the molar mass. Given $m = 25.0\ g$ and $M = 42.09\ g/mol$, then $n=\frac{25.0\ g}{42.09\ g/mol}$. $n=\frac{25.0}{42.09}\ mol\approx0.594\ mol$
Answer:
$0.594$