draw the pyranose β -anomer haworth projection from the fischer projection shown below. incorrect, 2…

Explanation:

Step1: Determine ring - formation

For a pyranose, a six - membered ring is formed. The carbonyl group (C=O) of the Fischer projection will react with the hydroxyl group on the fifth carbon atom to form the ring.

Step2: Identify anomer configuration

In the β - anomer, the anomeric hydroxyl group (the one on the new chiral center formed during ring - formation) is on the opposite side of the CH₂OH group attached to the ring.

Step3: Arrange substituents

In the Haworth projection of a pyranose, the groups on the right - hand side of the Fischer projection are below the plane of the ring and the groups on the left - hand side are above the plane of the ring.

The Haworth projection of the β - anomer of the given pyranose: The ring is a six - membered oxygen - containing ring (pyranose). The anomeric carbon has the hydroxyl group on the same side as the CH₂OH group attached to the ring (β - configuration). The other hydroxyl groups are arranged according to the Fischer projection rules (groups on the right in Fischer are below the ring and groups on the left are above the ring).

Answer:

A proper Haworth projection drawing of the β - anomer pyranose with the anomeric OH group on the same side as the terminal CH₂OH group and other OH groups arranged as per Fischer - to - Haworth conversion rules. (It's not possible to actually draw the structure in this text - based format, but the above description gives the steps to draw it).