what is the electron configuration for oxygen (o)? *\n1s^2 2s^2 2p^2\n1s^2 2s^2 2p^4\n1s^2 2s^2 2p^6\n1s^2…

what is the electron configuration for oxygen (o)? *\n1s^2 2s^2 2p^2\n1s^2 2s^2 2p^4\n1s^2 2s^2 2p^6\n1s^2 2s^2 2p^3

what is the electron configuration for oxygen (o)? *\n1s^2 2s^2 2p^2\n1s^2 2s^2 2p^4\n1s^2 2s^2 2p^6\n1s^2 2s^2 2p^3

Answer

Brief Explanations:

Oxygen has an atomic number of 8, meaning it has 8 electrons. The electron configuration follows the Aufbau principle. The 1s orbital holds 2 electrons, 2s holds 2, and the 2p orbital holds the remaining 4 (since 2 + 2 + 4 = 8). So the correct configuration is (1s^2 2s^2 2p^4).

Answer:

B. (1s^2 2s^2 2p^4) (assuming the second option is labeled B; if the options are unlabeled by letter, the second option in the list: (1s^2 2s^2 2p^4))