what is the electron configuration of the sodium atom after it loses an electron?\na. 1s²2s²2p⁶\nb…
what is the electron configuration of the sodium atom after it loses an electron?\na. 1s²2s²2p⁶\nb. he2s²2p5\nc. 1s²2s²2p⁶3s¹\nd. 1s²2s²2p²
Answer
Brief Explanations:
Sodium (Na) has an atomic number of 11. Its neutral - state electron configuration is $1s^{2}2s^{2}2p^{6}3s^{1}$. When it loses an electron, it loses the outermost 3s electron. So the electron configuration becomes $1s^{2}2s^{2}2p^{6}$, which is the same as the electron configuration of the noble gas neon.
Answer:
A. $1s^{2}2s^{2}2p^{6}$