the equation below shows hydrogen reacting with oxygen to produce water. 2h₂ + o₂ → 2h₂o. if 16 mol of…

the equation below shows hydrogen reacting with oxygen to produce water. 2h₂ + o₂ → 2h₂o. if 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced? 4.0 mol 8.0 mol 16 mol 32 mol

the equation below shows hydrogen reacting with oxygen to produce water. 2h₂ + o₂ → 2h₂o. if 16 mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced? 4.0 mol 8.0 mol 16 mol 32 mol

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $2H_2 + O_2\rightarrow2H_2O$, the mole - ratio of $O_2$ to $H_2O$ is $1:2$.

Step2: Calculate moles of water

Given $n_{O_2}=16$ mol. Using the mole - ratio, $n_{H_2O}=2\times n_{O_2}$. So $n_{H_2O}=2\times16$ mol.

Answer:

D. 32 mol