the equation below shows lithium reacting with nitrogen to produce lithium nitride. 6li + n₂ → 2li₃n. if 12…

the equation below shows lithium reacting with nitrogen to produce lithium nitride. 6li + n₂ → 2li₃n. if 12 mol of lithium were reacted with excess nitrogen gas, how many moles of lithium nitride would be produced? 4.0 mol 6.0 mol 12 mol 36 mol

the equation below shows lithium reacting with nitrogen to produce lithium nitride. 6li + n₂ → 2li₃n. if 12 mol of lithium were reacted with excess nitrogen gas, how many moles of lithium nitride would be produced? 4.0 mol 6.0 mol 12 mol 36 mol

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $6Li + N_2\rightarrow2Li_3N$, the mole - ratio of $Li$ to $Li_3N$ is $6:2$ or $3:1$.

Step2: Set up proportion

Let $x$ be the number of moles of $Li_3N$ produced. We know the number of moles of $Li$ is 12 mol. Using the mole - ratio, we have the proportion $\frac{3}{1}=\frac{12}{x}$.

Step3: Solve for $x$

Cross - multiply: $3x = 12\times1$. Then $x=\frac{12}{3}=4$ mol.

Answer:

A. 4.0 mol