the equation shows the reaction between zinc metal and hydrochloric acid. zn(s) + 2hcl(aq) → zncl₂(aq) +…

the equation shows the reaction between zinc metal and hydrochloric acid. zn(s) + 2hcl(aq) → zncl₂(aq) + h₂(g) what is the theoretical yield of hydrogen gas if 5.00 mol of zinc are added to an excess of hydrochloric acid? 5.05 g 10.1 g 182 g 682 g

the equation shows the reaction between zinc metal and hydrochloric acid. zn(s) + 2hcl(aq) → zncl₂(aq) + h₂(g) what is the theoretical yield of hydrogen gas if 5.00 mol of zinc are added to an excess of hydrochloric acid? 5.05 g 10.1 g 182 g 682 g

Answer

Answer:

B. 10.1 g

Explanation:

Step1: Determine mole - ratio

From the equation $Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq) + H_2(g)$, the mole - ratio of $Zn$ to $H_2$ is 1:1.

Step2: Calculate moles of $H_2$

Given 5.00 mol of $Zn$, moles of $H_2$ produced is also 5.00 mol since the mole - ratio is 1:1.

Step3: Calculate mass of $H_2$

The molar mass of $H_2$ is $M = 2\times1\ g/mol= 2\ g/mol$. Mass $m=n\times M$, so $m = 5.00\ mol\times2\ g/mol=10.0\ g\approx10.1\ g$.