essay 2 points\nconsider the following chemical reaction:\n2b₅h₉(ℓ) + 12o₂(g) → 5b₂o₃(s) + 9h₂o(ℓ)\nhow many…

essay 2 points\nconsider the following chemical reaction:\n2b₅h₉(ℓ) + 12o₂(g) → 5b₂o₃(s) + 9h₂o(ℓ)\nhow many moles of h₂o would be produced if 9.0 moles of o₂ were used in the reaction?\nedit view insert format tools table\n12pt paragraph b i u a t²

essay 2 points\nconsider the following chemical reaction:\n2b₅h₉(ℓ) + 12o₂(g) → 5b₂o₃(s) + 9h₂o(ℓ)\nhow many moles of h₂o would be produced if 9.0 moles of o₂ were used in the reaction?\nedit view insert format tools table\n12pt paragraph b i u a t²

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $2B_5H_9(\ell)+12O_2(g)\to5B_2O_3(s)+9H_2O(\ell)$, the mole - ratio of $O_2$ to $H_2O$ is $12:9$ or $\frac{4}{3}$.

Step2: Set up proportion

Let $x$ be the number of moles of $H_2O$ produced. We have the proportion $\frac{12}{9}=\frac{9.0}{x}$. Cross - multiply gives $12x = 9\times9.0$.

Step3: Solve for $x$

$x=\frac{9\times9.0}{12}=\frac{81}{12}=6.75$.

Answer:

$6.75$