fill in the missing symbol in this nuclear chemical equation.\n$_{62}^{147}sm\rightarrow_{60}^{143}nd+square$
fill in the missing symbol in this nuclear chemical equation.\n$_{62}^{147}sm\rightarrow_{60}^{143}nd+square$
Answer
Explanation:
Step1: Balance mass - number
The mass - number on the left - hand side is 147. On the right - hand side, the mass - number of Nd is 143. Let the mass - number of the unknown particle be $x$. Then $147=143 + x$, so $x = 147-143=4$.
Step2: Balance atomic number
The atomic number on the left - hand side is 62. The atomic number of Nd is 60. Let the atomic number of the unknown particle be $y$. Then $62=60 + y$, so $y = 62 - 60=2$.
Step3: Identify the particle
A particle with mass - number 4 and atomic number 2 is an alpha particle, represented as $_{2}^{4}\alpha$.
Answer:
$_{2}^{4}\alpha$