fill in the name and empirical formula of each ionic compound that could be formed from the ions in this…

fill in the name and empirical formula of each ionic compound that could be formed from the ions in this table: cation: fe 3+, pb 4+, ca 2+; anion: cro 4 2-, so 4 2-, bro 3 -; some ionic compounds; empirical formula; name of compound
Answer
Explanation:
Step1: Recall ion - naming rules
Cations are named as the element name followed by the charge in Roman numerals if the metal has multiple oxidation states. Anions are named with an -ate or -ite suffix for polyatomic anions or -ide for simple anions.
Step2: Name the cations
$Fe^{3 + }$ is iron(III) ion, $Pb^{4+}$ is lead(IV) ion, $Ca^{2+}$ is calcium ion.
Step3: Name the anions
$CrO_{4}^{2 - }$ is chromate ion, $SO_{4}^{2 - }$ is sulfate ion, $BrO_{3}^{-}$ is bromate ion.
Step4: Determine empirical formulas
For a compound formed between a cation $M^{m+}$ and an anion $A^{n - }$, the empirical formula is $M_{n}A_{m}$ (the least - common - multiple method to balance the charges).
- For $Fe^{3+}$ and $CrO_{4}^{2 - }$, the empirical formula is $Fe_{2}(CrO_{4})_{3}$ and the name is iron(III) chromate.
- For $Fe^{3+}$ and $SO_{4}^{2 - }$, the empirical formula is $Fe_{2}(SO_{4})_{3}$ and the name is iron(III) sulfate.
- For $Fe^{3+}$ and $BrO_{3}^{-}$, the empirical formula is $Fe(BrO_{3})_{3}$ and the name is iron(III) bromate.
- For $Pb^{4+}$ and $CrO_{4}^{2 - }$, the empirical formula is $Pb(CrO_{4})_{2}$ and the name is lead(IV) chromate.
- For $Pb^{4+}$ and $SO_{4}^{2 - }$, the empirical formula is $Pb(SO_{4})_{2}$ and the name is lead(IV) sulfate.
- For $Pb^{4+}$ and $BrO_{3}^{-}$, the empirical formula is $Pb(BrO_{3})_{4}$ and the name is lead(IV) bromate.
- For $Ca^{2+}$ and $CrO_{4}^{2 - }$, the empirical formula is $CaCrO_{4}$ and the name is calcium chromate.
- For $Ca^{2+}$ and $SO_{4}^{2 - }$, the empirical formula is $CaSO_{4}$ and the name is calcium sulfate.
- For $Ca^{2+}$ and $BrO_{3}^{-}$, the empirical formula is $Ca(BrO_{3})_{2}$ and the name is calcium bromate.
Answer:
| Cation | Anion | Empirical Formula | Name of Compound |
|---|---|---|---|
| $Fe^{3 + }$ | $CrO_{4}^{2 - }$ | $Fe_{2}(CrO_{4})_{3}$ | iron(III) chromate |
| $Fe^{3 + }$ | $SO_{4}^{2 - }$ | $Fe_{2}(SO_{4})_{3}$ | iron(III) sulfate |
| $Fe^{3 + }$ | $BrO_{3}^{-}$ | $Fe(BrO_{3})_{3}$ | iron(III) bromate |
| $Pb^{4+}$ | $CrO_{4}^{2 - }$ | $Pb(CrO_{4})_{2}$ | lead(IV) chromate |
| $Pb^{4+}$ | $SO_{4}^{2 - }$ | $Pb(SO_{4})_{2}$ | lead(IV) sulfate |
| $Pb^{4+}$ | $BrO_{3}^{-}$ | $Pb(BrO_{3})_{4}$ | lead(IV) bromate |
| $Ca^{2+}$ | $CrO_{4}^{2 - }$ | $CaCrO_{4}$ | calcium chromate |
| $Ca^{2+}$ | $SO_{4}^{2 - }$ | $CaSO_{4}$ | calcium sulfate |
| $Ca^{2+}$ | $BrO_{3}^{-}$ | $Ca(BrO_{3})_{2}$ | calcium bromate |