find the mass of sodium acetate which is required to make 500 ml of 0.475 molar aqueous solution. the molar…

Explanation:

Step1: Convert volume to liters

The volume $V = 500\ ml=0.5\ L$.

Step2: Calculate the number of moles

The molarity formula is $M=\frac{n}{V}$, where $M$ is molarity, $n$ is the number of moles and $V$ is volume in liters. Rearranging for $n$, we get $n = M\times V$. Given $M = 0.475\ mol/L$ and $V=0.5\ L$, then $n=0.475\ mol/L\times0.5\ L = 0.2375\ mol$.

Step3: Calculate the mass

The mass $m$ is calculated using the formula $m=n\times M_m$, where $M_m$ is the molar - mass. Given $n = 0.2375\ mol$ and $M_m=82.0245\ g/mol$, then $m=0.2375\ mol\times82.0245\ g/mol\approx19.48\ g$.

Answer:

d. None of the above