find the new concentration of a solution if 25.0 ml of water is added to 125.0 ml of 0.150 m nacl…

Explanation:

Step1: Calculate final volume

The initial volume of the solution $V_1 = 125.0\ mL$ and the volume of water added $V_{added}=25.0\ mL$. The final volume $V_2$ is the sum of the initial volume and the added - volume. $V_2=V_1 + V_{added}$ $V_2=125.0\ mL+25.0\ mL$ $V_2 = 150.0\ mL$

Step2: Use dilution formula

The dilution formula is $M_1V_1 = M_2V_2$, where $M_1 = 0.150\ M$ is the initial concentration, $V_1 = 125.0\ mL$, $V_2 = 150.0\ mL$, and $M_2$ is the final concentration we want to find. We can re - arrange the formula to solve for $M_2$: $M_2=\frac{M_1V_1}{V_2}$ Substitute the values: $M_2=\frac{0.150\ M\times125.0\ mL}{150.0\ mL}$ $M_2 = 0.125\ M$

Answer:

The final volume is $150.0\ mL$ and the new concentration is $0.125\ M$.