a flexible container holds 1.50 moles of air and is currently expanded to 13.5 l in volume. what is the…

a flexible container holds 1.50 moles of air and is currently expanded to 13.5 l in volume. what is the volume of the container if the number of moles of air is doubled to 3.00 moles under the same temperature and pressure conditions? v2 = ? l

a flexible container holds 1.50 moles of air and is currently expanded to 13.5 l in volume. what is the volume of the container if the number of moles of air is doubled to 3.00 moles under the same temperature and pressure conditions? v2 = ? l

Answer

Explanation:

Step1: Identify the gas - law relationship

At constant temperature and pressure, the volume of a gas is directly proportional to the number of moles (Avogadro's law: $\frac{V_1}{n_1}=\frac{V_2}{n_2}$).

Step2: Define the given values

$n_1 = 1.50$ moles, $V_1=13.5$ L, $n_2 = 3.00$ moles.

Step3: Rearrange the formula to solve for $V_2$

$V_2=\frac{n_2V_1}{n_1}$.

Step4: Substitute the values into the formula

$V_2=\frac{3.00\ mol\times13.5\ L}{1.50\ mol}$. $V_2 = 27.0$ L.

Answer:

27.0