the following balanced equation shows the decomposition of ammonia (nh₃) into nitrogen (n₂) and hydrogen…

the following balanced equation shows the decomposition of ammonia (nh₃) into nitrogen (n₂) and hydrogen (h₂). 2nh₃ → n₂ + 3h₂ a quantity of nh₃ decomposes to produce 0.0351 mol n₂. how many moles of h₂ are produced? 0.0351 mol h₂ 0.0117 mol h₂ 0.105 mol h₂ 0.0702 mol h₂ done

the following balanced equation shows the decomposition of ammonia (nh₃) into nitrogen (n₂) and hydrogen (h₂). 2nh₃ → n₂ + 3h₂ a quantity of nh₃ decomposes to produce 0.0351 mol n₂. how many moles of h₂ are produced? 0.0351 mol h₂ 0.0117 mol h₂ 0.105 mol h₂ 0.0702 mol h₂ done

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $2NH_3\rightarrow N_2 + 3H_2$, the mole - ratio of $N_2$ to $H_2$ is $n_{N_2}:n_{H_2}=1:3$.

Step2: Calculate moles of $H_2$

We know $n_{N_2} = 0.0351$ mol. Using the mole - ratio, $n_{H_2}=3\times n_{N_2}$. So $n_{H_2}=3\times0.0351$ mol. $n_{H_2}=0.1053\approx0.105$ mol

Answer:

0.105 mol $H_2$