the following balanced equation shows the formation of ammonia. n₂ + 3h₂ → 2nh₃ how many moles of nitrogen…

the following balanced equation shows the formation of ammonia. n₂ + 3h₂ → 2nh₃ how many moles of nitrogen are needed to completely convert 6.34 mol of hydrogen? 1.02 mol 2.11 mol 12.68 mol 19.02 mol

the following balanced equation shows the formation of ammonia. n₂ + 3h₂ → 2nh₃ how many moles of nitrogen are needed to completely convert 6.34 mol of hydrogen? 1.02 mol 2.11 mol 12.68 mol 19.02 mol

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced equation $N_2 + 3H_2\rightarrow2NH_3$, the mole - ratio of $N_2$ to $H_2$ is $n_{N_2}:n_{H_2}=1:3$.

Step2: Calculate moles of nitrogen

We know $n_{H_2} = 6.34$ mol. Using the mole - ratio, $n_{N_2}=\frac{n_{H_2}}{3}$. Substitute $n_{H_2}=6.34$ mol into the formula: $n_{N_2}=\frac{6.34}{3}\approx2.11$ mol.

Answer:

B. 2.11 mol