for the following electron configuration, identify the element and determine if it is in the ground state or…

for the following electron configuration, identify the element and determine if it is in the ground state or excited state. 1s²2s²2p⁶3s²3p⁶3d¹ a k, ground state b k, excited state c ca, ground state d ca, excited state e sc, ground state

for the following electron configuration, identify the element and determine if it is in the ground state or excited state. 1s²2s²2p⁶3s²3p⁶3d¹ a k, ground state b k, excited state c ca, ground state d ca, excited state e sc, ground state

Answer

Answer:

B. K, excited state

Explanation:

Step1: Calculate the total number of electrons

The electron configuration is (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{1}). Sum the exponents: (2 + 2+6 + 2+6 + 1=19) electrons.

Step2: Identify the element

The element with 19 electrons is potassium ((K)).

Step3: Check the ground - state electron configuration

The ground - state electron configuration of (K) is (1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{1}). In the given configuration ((1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{1})), an electron has been promoted from the (4s) orbital (lower energy) to the (3d) orbital (higher energy). So, it is in the excited state.