which of the following isotopes have 8 neutrons in the nucleus?\no o-15\no o-17\no c-13\no c-14

Answer:

C. C - 13

Explanation:

Step1: Recall neutron - proton relationship

The number of neutrons ($n$) in an isotope is given by $n = A - Z$, where $A$ is the mass number and $Z$ is the atomic number.

Step2: Determine atomic numbers

The atomic number of oxygen ($O$) is $Z_O=8$, and the atomic number of carbon ($C$) is $Z_C = 6$.

Step3: Calculate neutrons for O - 15

For O - 15, $A = 15$ and $Z = 8$. Then $n=15 - 8=7$.

Step4: Calculate neutrons for O - 17

For O - 17, $A = 17$ and $Z = 8$. Then $n=17 - 8 = 9$.

Step5: Calculate neutrons for C - 13

For C - 13, $A = 13$ and $Z = 6$. Then $n=13 - 6=7$.

Step6: Calculate neutrons for C - 14

For C - 14, $A = 14$ and $Z = 6$. Then $n=14 - 6 = 8$.