which of the following isotopes have 8 neutrons in the nucleus?\no - 15\no - 17\nc - 13\nc - 14

Answer:

D. C-14

Explanation:

Step1: Recall neutron - proton relationship

The mass number ($A$) of an isotope is the sum of the number of protons ($p$) and neutrons ($n$), i.e., $A=p + n$.

Step2: Determine proton numbers

Oxygen ($O$) has an atomic number of $8$, so $p_O = 8$. Carbon ($C$) has an atomic number of $6$, so $p_C=6$.

Step3: Calculate neutrons for O - 15

For O - 15, $A = 15$ and $p = 8$. Then $n=A - p=15 - 8 = 7$.

Step4: Calculate neutrons for O - 17

For O - 17, $A = 17$ and $p = 8$. Then $n=A - p=17 - 8 = 9$.

Step5: Calculate neutrons for C - 13

For C - 13, $A = 13$ and $p = 6$. Then $n=A - p=13 - 6 = 7$.

Step6: Calculate neutrons for C - 14

For C - 14, $A = 14$ and $p = 6$. Then $n=A - p=14 - 6 = 8$.