2 for the following reactions:\ni. predict the product of the acid - base reaction (clearly showing…

2 for the following reactions:\ni. predict the product of the acid - base reaction (clearly showing important lone pairs and bonds).\nii. redraw the reactants (clearly showing important lone pairs and bonds) and use arrow pushing to show the electron movement and changes in bonding.\niii. determine which side of the equilibrium is favored.\na.

2 for the following reactions:\ni. predict the product of the acid - base reaction (clearly showing important lone pairs and bonds).\nii. redraw the reactants (clearly showing important lone pairs and bonds) and use arrow pushing to show the electron movement and changes in bonding.\niii. determine which side of the equilibrium is favored.\na.

Answer

Explanation:

Step1: Predict product

The lithium - containing compound is a strong base and the alkene (the other reactant) has a relatively acidic hydrogen on the carbon adjacent to the double - bond. The base will abstract this hydrogen. The product will be an organolithium compound and hydrogen gas. The product structure should show the new C - Li bond and the formation of $H_2$.

Step2: Redraw reactants and show electron movement

Redraw the n - butyllithium ($n - BuLi$) showing the lone pair on the carbon (since it is a carbanion) and the alkene showing the double - bond. The arrow should start from the lone pair on the carbon of $n - BuLi$ and go towards the hydrogen on the alkene. Another arrow should start from the C - H bond of the alkene and go towards the carbon of the double - bond, and a third arrow should start from the double - bond and go towards the lithium, forming a new C - Li bond.

Step3: Determine equilibrium side

The equilibrium will favor the side with the weaker acid - base pair. The hydrogen gas ($H_2$) is a very weak acid ($pK_a\approx 35$). The acid on the reactant side (the hydrogen on the alkene adjacent to the double - bond) is stronger than $H_2$. So, the equilibrium will favor the product side.

Answer:

i. The product is an organolithium compound and hydrogen gas. ii. Redraw reactants with lone - pairs on the carbanion of $n - BuLi$ and double - bond in the alkene. Use arrows to show electron movement from the lone - pair on the carbanion to the acidic hydrogen, from the C - H bond to the double - bond carbon, and from the double - bond to the lithium. iii. The equilibrium favors the product side.