which of the following is not a true statement?\n3.42 moles co = 84.0 g\n0.75 moles h₂co₃ = 47 g\n0.2 moles…

Explanation:

Step1: Calculate molar - mass of CO

The molar mass of CO: C has a molar mass of 12.01 g/mol and O has a molar mass of 16.00 g/mol. So, $M_{CO}=12.01 + 16.00=28.01$ g/mol.

Step2: Calculate mass of 3.42 moles of CO

Using the formula $m = n\times M$, where $n = 3.42$ mol and $M = 28.01$ g/mol. Then $m=3.42\times28.01\approx95.8$ g.

Step3: Calculate molar - mass of $H_2CO_3$

The molar mass of $H_2CO_3$: 2 H (each with molar mass 1.01 g/mol), 1 C (12.01 g/mol) and 3 O (each with molar mass 16.00 g/mol). So, $M_{H_2CO_3}=2\times1.01 + 12.01+3\times16.00=2.02 + 12.01+48.00 = 62.03$ g/mol.

Step4: Calculate mass of 0.75 moles of $H_2CO_3$

Using the formula $m = n\times M$, where $n = 0.75$ mol and $M = 62.03$ g/mol. Then $m = 0.75\times62.03\approx46.5$ g $\approx47$ g.

Step5: Calculate molar - mass of $O_2$

The molar mass of $O_2$ is $M_{O_2}=2\times16.00 = 32$ g/mol.

Step6: Calculate mass of 0.2 moles of $O_2$

Using the formula $m = n\times M$, where $n = 0.2$ mol and $M = 32$ g/mol. Then $m=0.2\times32 = 6.4$ g $\approx6$ g.

Answer:

$3.42$ moles $CO = 84.0$ g