forming ionic compounds worksheet\n1. write the correct formula in each corresponding box.\n| | zinc | iron…

Explanation:

Step1: Determine ion charges

Zinc has a charge of +2 ($Zn^{2 +}$), Iron (II) has a charge of +2 ($Fe^{2+}$), Iron (III) has a charge of +3 ($Fe^{3+}$), Gallium has a charge of +3 ($Ga^{3+}$), Silver has a charge of +1 ($Ag^{+}$). Chloride is $Cl^{-}$, Acetate is $C_{2}H_{3}O_{2}^{-}$, Oxide is $O^{2 -}$, Nitrate is $NO_{3}^{-}$, Nitride is $N^{3 -}$, Sulfate is $SO_{4}^{2 -}$. Lithium has a charge of +1 ($Li^{+}$), Cobalt (III) has a charge of +3 ($Co^{3+}$), Copper (II) has a charge of +2 ($Cu^{2+}$), Titanium (II) has a charge of +2 ($Ti^{2+}$), Calcium has a charge of +2 ($Ca^{2+}$).

Step2: Write formulas for table

Zinc

• Chloride: $ZnCl_{2}$ (2 $Cl^{-}$ balance $Zn^{2+}$)
• Acetate: $Zn(C_{2}H_{3}O_{2}){2}$ (2 $C{2}H_{3}O_{2}^{-}$ balance $Zn^{2+}$)
• Oxide: $ZnO$ (1 $O^{2 -}$ balances $Zn^{2+}$)
• Nitrate: $Zn(NO_{3}){2}$ (2 $NO{3}^{-}$ balance $Zn^{2+}$)
• Nitride: $Zn_{3}N_{2}$ (2 $N^{3 -}$ and 3 $Zn^{2+}$ for charge - balance)
• Sulfate: $ZnSO_{4}$ (1 $SO_{4}^{2 -}$ balances $Zn^{2+}$)

Iron (II)

• Chloride: $FeCl_{2}$ (2 $Cl^{-}$ balance $Fe^{2+}$)
• Acetate: $Fe(C_{2}H_{3}O_{2}){2}$ (2 $C{2}H_{3}O_{2}^{-}$ balance $Fe^{2+}$)
• Oxide: $FeO$ (1 $O^{2 -}$ balances $Fe^{2+}$)
• Nitrate: $Fe(NO_{3}){2}$ (2 $NO{3}^{-}$ balance $Fe^{2+}$)
• Nitride: $Fe_{3}N_{2}$ (2 $N^{3 -}$ and 3 $Fe^{2+}$ for charge - balance)
• Sulfate: $FeSO_{4}$ (1 $SO_{4}^{2 -}$ balances $Fe^{2+}$)

Iron (III)

• Chloride: $FeCl_{3}$ (3 $Cl^{-}$ balance $Fe^{3+}$)
• Acetate: $Fe(C_{2}H_{3}O_{2}){3}$ (3 $C{2}H_{3}O_{2}^{-}$ balance $Fe^{3+}$)
• Oxide: $Fe_{2}O_{3}$ (3 $O^{2 -}$ and 2 $Fe^{3+}$ for charge - balance)
• Nitrate: $Fe(NO_{3}){3}$ (3 $NO{3}^{-}$ balance $Fe^{3+}$)
• Nitride: $FeN$ (1 $N^{3 -}$ and 1 $Fe^{3+}$ for charge - balance)
• Sulfate: $Fe_{2}(SO_{4}){3}$ (3 $SO{4}^{2 -}$ and 2 $Fe^{3+}$ for charge - balance)

Gallium

• Chloride: $GaCl_{3}$ (3 $Cl^{-}$ balance $Ga^{3+}$)
• Acetate: $Ga(C_{2}H_{3}O_{2}){3}$ (3 $C{2}H_{3}O_{2}^{-}$ balance $Ga^{3+}$)
• Oxide: $Ga_{2}O_{3}$ (3 $O^{2 -}$ and 2 $Ga^{3+}$ for charge - balance)
• Nitrate: $Ga(NO_{3}){3}$ (3 $NO{3}^{-}$ balance $Ga^{3+}$)
• Nitride: $GaN$ (1 $N^{3 -}$ and 1 $Ga^{3+}$ for charge - balance)
• Sulfate: $Ga_{2}(SO_{4}){3}$ (3 $SO{4}^{2 -}$ and 2 $Ga^{3+}$ for charge - balance)

Silver

• Chloride: $AgCl$ (1 $Cl^{-}$ balances $Ag^{+}$)
• Acetate: $AgC_{2}H_{3}O_{2}$ (1 $C_{2}H_{3}O_{2}^{-}$ balances $Ag^{+}$)
• Oxide: $Ag_{2}O$ (1 $O^{2 -}$ and 2 $Ag^{+}$ for charge - balance)
• Nitrate: $AgNO_{3}$ (1 $NO_{3}^{-}$ balances $Ag^{+}$)
• Nitride: $Ag_{3}N$ (1 $N^{3 -}$ and 3 $Ag^{+}$ for charge - balance)
• Sulfate: $Ag_{2}SO_{4}$ (1 $SO_{4}^{2 -}$ and 2 $Ag^{+}$ for charge - balance)

Step3: Write formulas for part 2

a. Lithium Acetate

$LiC_{2}H_{3}O_{2}$ (1 $Li^{+}$ and 1 $C_{2}H_{3}O_{2}^{-}$)

b. Cobalt (III) Chloride

$CoCl_{3}$ (3 $Cl^{-}$ balance $Co^{3+}$)

c. Copper (II) Chlorate

$Cu(ClO_{3}){2}$ (2 $ClO{3}^{-}$ balance $Cu^{2+}$)

d. Titanium (II) Selenide

$TiSe$ (1 $Se^{2 -}$ balances $Ti^{2+}$)

e. Calcium Oxide

$CaO$ (1 $O^{2 -}$ balances $Ca^{2+}$)

Answer:

	Zinc	Iron (II)	Iron (III)	Gallium	Silver
Chloride	$ZnCl_{2}$	$FeCl_{2}$	$FeCl_{3}$	$GaCl_{3}$	$AgCl$
Acetate	$Zn(C_{2}H_{3}O_{2})_{2}$	$Fe(C_{2}H_{3}O_{2})_{2}$	$Fe(C_{2}H_{3}O_{2})_{3}$	$Ga(C_{2}H_{3}O_{2})_{3}$	$AgC_{2}H_{3}O_{2}$
Oxide	$ZnO$	$FeO$	$Fe_{2}O_{3}$	$Ga_{2}O_{3}$	$Ag_{2}O$
Nitrate	$Zn(NO_{3})_{2}$	$Fe(NO_{3})_{2}$	$Fe(NO_{3})_{3}$	$Ga(NO_{3})_{3}$	$AgNO_{3}$
Nitride	$Zn_{3}N_{2}$	$Fe_{3}N_{2}$	$FeN$	$GaN$	$Ag_{3}N$
Sulfate	$ZnSO_{4}$	$FeSO_{4}$	$Fe_{2}(SO_{4})_{3}$	$Ga_{2}(SO_{4})_{3}$	$Ag_{2}SO_{4}$

a. $LiC_{2}H_{3}O_{2}$ b. $CoCl_{3}$ c. $Cu(ClO_{3})_{2}$ d. $TiSe$ e. $CaO$