3 formula 12.5 points what volume of nitrogen, in l, will 0.655 moles of nitrogen occupy at 25.9°c and 0.192…

Explanation:

Step1: Convert temperature to Kelvin

$T=(25.9 + 273.15)\text{ K}=299.05\text{ K}$

Step2: Use the ideal - gas law $PV = nRT$

We know that $P = 0.192\text{ atm}$, $n = 0.655\text{ mol}$, $R=0.0821\frac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}$, and $T = 299.05\text{ K}$. We want to find $V$. Rearranging the ideal - gas law for $V$ gives $V=\frac{nRT}{P}$.

Step3: Substitute values into the formula

$V=\frac{0.655\text{ mol}\times0.0821\frac{\text{L}\cdot\text{atm}}{\text{mol}\cdot\text{K}}\times299.05\text{ K}}{0.192\text{ atm}}$ $V=\frac{0.655\times0.0821\times299.05}{0.192}\text{ L}$ $V=\frac{16.117}{0.192}\text{ L}\approx83.94\text{ L}$

Answer:

$83.94$