what is the formula for the ionic compound composed of aluminum cations and sulfate anions.\naiso₄₂\nal₂(so₄)…
what is the formula for the ionic compound composed of aluminum cations and sulfate anions.\naiso₄₂\nal₂(so₄)₂\nal₂(so₄)₃\naiso₄\nquestion 16\n1 pts\na compound contains an unknown ion x and has the formula x(co₃)₂. ion x contains 46 electrons. what is ion x?\npb⁴⁺\nos⁴⁺\nsn⁴⁺\npt⁴⁺\nsn²⁺
Answer
Explanation:
Step1: Determine aluminum ion charge
Aluminum forms a $Al^{3 + }$ ion as it loses 3 electrons to achieve a stable electron - configuration.
Step2: Determine sulfate ion charge
The sulfate ion is $SO_{4}^{2 - }$.
Step3: Balance charges
To balance the charges in the ionic compound, we need 2 aluminum ions ($2\times( + 3)=+6$) and 3 sulfate ions ($3\times(- 2)= - 6$). So the formula is $Al_{2}(SO_{4})_{3}$.
Step4: Analyze the second question
The carbonate ion $CO_{3}^{2 - }$ has a charge of - 2. In the compound $X(CO_{3})_{2}$, the overall charge of the carbonate part is $2\times(-2)= - 4$. So ion $X$ has a charge of + 4.
Step5: Determine the number of protons of ion X
An ion with a + 4 charge has 4 fewer electrons than protons. If the ion has 46 electrons, then the number of protons is $46 + 4=50$. The element with 50 protons is tin ($Sn$), and the ion is $Sn^{4+}$.
Answer:
Question 15: C. $Al_{2}(SO_{4})_{3}$ Question 16: C. $Sn^{4+}$