formula 1 point how many atoms of aluminum wire would you have if you had 13.91 moles of aluminum? when…
formula 1 point how many atoms of aluminum wire would you have if you had 13.91 moles of aluminum? when entering answers - follow this format!! example 1.00*10^23 round to two decimals, then x10 and power *10^##
Answer
Explanation:
Step1: Recall Avogadro's number
Avogadro's number $N_A = 6.022\times10^{23}$ atoms/mol.
Step2: Calculate the number of atoms
The number of atoms $N$ of aluminum is given by $N = n\times N_A$, where $n = 13.91$ mol. So $N=13.91\times6.022\times 10^{23}$. $N = 13.91\times6.022\times10^{23}=83.76602\times10^{23}$. Rounding to two - decimals, we get $83.77\times10^{23}$.
Answer:
$83.77*10^{23}$