a gas cylinder contains 2.0 mol of gas x and 6.0 mol of gas y at a total pressure of 2.1 atm. what is the…

a gas cylinder contains 2.0 mol of gas x and 6.0 mol of gas y at a total pressure of 2.1 atm. what is the partial pressure of gas y? use $\frac{p_{g}}{p_{t}}=\frac{n_{g}}{n_{t}}$. 0.50 atm 1.6 atm 2.1 atm 2.8 atm

a gas cylinder contains 2.0 mol of gas x and 6.0 mol of gas y at a total pressure of 2.1 atm. what is the partial pressure of gas y? use $\frac{p_{g}}{p_{t}}=\frac{n_{g}}{n_{t}}$. 0.50 atm 1.6 atm 2.1 atm 2.8 atm

Answer

Explanation:

Step1: Calculate total moles

$n_T=n_X + n_Y=2.0\ mol+6.0\ mol = 8.0\ mol$

Step2: Calculate mole - fraction of gas Y

$x_Y=\frac{n_Y}{n_T}=\frac{6.0\ mol}{8.0\ mol}=0.75$

Step3: Calculate partial pressure of gas Y

According to Dalton's law of partial pressures $P_Y = x_Y\times P_T$. Given $P_T = 2.1\ atm$, so $P_Y=0.75\times2.1\ atm = 1.575\ atm\approx1.6\ atm$

Answer:

B. 1.6 atm