give the systematic name of each of the compounds.\nfecl₂:\npbo₂:\ncubr:\nau₂s₃:

give the systematic name of each of the compounds.\nfecl₂:\npbo₂:\ncubr:\nau₂s₃:

give the systematic name of each of the compounds.\nfecl₂:\npbo₂:\ncubr:\nau₂s₃:

Answer

Brief Explanations:

  1. For $FeCl_2$, iron has a +2 oxidation - state in this compound, so it is named iron(II) chloride.
  2. In $PbO_2$, lead has a +4 oxidation - state, and it is named lead(IV) oxide.
  3. For $CuBr$, copper has a +1 oxidation - state, and it is named copper(I) bromide.
  4. In $Au_2S_3$, gold has a +3 oxidation - state, and it is named gold(III) sulfide.

Answer:

  1. Iron(II) chloride
  2. Lead(IV) oxide
  3. Copper(I) bromide
  4. Gold(III) sulfide