given 367 g of al2o3, determine the number of moles of al2o3.\n1 mol al2o3 = 101.96 g al2o3\n? mol al2o3 =…

given 367 g of al2o3, determine the number of moles of al2o3.\n1 mol al2o3 = 101.96 g al2o3\n? mol al2o3 = 367 g al2o3\nround your answer to two decimal places.

given 367 g of al2o3, determine the number of moles of al2o3.\n1 mol al2o3 = 101.96 g al2o3\n? mol al2o3 = 367 g al2o3\nround your answer to two decimal places.

Answer

Explanation:

Step1: Identify the conversion factor

We know that 1 mol of $\ce{Al2O3}$ has a mass of 101.96 g.

Step2: Set up the calculation

To find the number of moles, we divide the given mass by the molar - mass. Let $n$ be the number of moles, $m = 367$ g be the given mass, and $M=101.96$ g/mol be the molar mass. The formula is $n=\frac{m}{M}$. $n=\frac{367\ g}{101.96\ g/mol}$

Step3: Calculate the result

$n = 3.60$ mol

Answer:

3.60