given that the molar mass of naoh is 40.00 g/mol, what mass of naoh is needed to make 2.500 l of a 2.000 m…

given that the molar mass of naoh is 40.00 g/mol, what mass of naoh is needed to make 2.500 l of a 2.000 m naoh solution? use molarity = \\frac{moles of solute}{liters of solution}.\n0.1250 g\n5.000 g\n32.00 g\n200.0 g

given that the molar mass of naoh is 40.00 g/mol, what mass of naoh is needed to make 2.500 l of a 2.000 m naoh solution? use molarity = \\frac{moles of solute}{liters of solution}.\n0.1250 g\n5.000 g\n32.00 g\n200.0 g

Answer

Explanation:

Step1: Calculate moles of NaOH

We know that molarity $M=\frac{n}{V}$, where $M$ is molarity, $n$ is moles of solute and $V$ is volume of solution in liters. Given $M = 2.000\ M$ and $V=2.500\ L$. Rearranging for $n$, we get $n = M\times V$. $n=2.000\ mol/L\times2.500\ L = 5.000\ mol$

Step2: Calculate mass of NaOH

We know that mass $m=n\times M_m$, where $n$ is moles and $M_m$ is molar - mass. Given $n = 5.000\ mol$ and $M_m=40.00\ g/mol$. $m = 5.000\ mol\times40.00\ g/mol=200.0\ g$

Answer:

D. 200.0 g