which half - reaction correctly describes an oxidation?\nca(s)+2e⁻→ca²⁺(aq)\nbr₂ + 2e⁻→2br⁻\nna⁺(aq)→na(s)+e⁻…
which half - reaction correctly describes an oxidation?\nca(s)+2e⁻→ca²⁺(aq)\nbr₂ + 2e⁻→2br⁻\nna⁺(aq)→na(s)+e⁻\ncr(s)→cr³⁺(aq)+3e⁻
Answer
Answer:
D. $\ce{Cr(s)\longrightarrow Cr^{3 + }(aq)+3e^{-}}$
Explanation:
Step1: Recall oxidation definition
Oxidation is loss of electrons.
Step2: Analyze each option
- Option A: $\ce{Ca(s)+2e^{-}\longrightarrow Ca^{2 + }(aq)}$ is gain of electrons (reduction).
- Option B: $\ce{Br2 + 2e^{-}\longrightarrow 2Br^{-}}$ is gain of electrons (reduction).
- Option C: $\ce{Na^{+}(aq)\longrightarrow Na(s)+e^{-}}$ is gain of electrons (reduction).
- Option D: $\ce{Cr(s)\longrightarrow Cr^{3 + }(aq)+3e^{-}}$ shows chromium losing 3 electrons, which is oxidation.