which half - reaction correctly represents reduction?\na) mn^{4+}→mn^{3+}+e^{-}\nb) mn^{4+}→mn^{7+}+3e^{-}\nc…

which half - reaction correctly represents reduction?\na) mn^{4+}→mn^{3+}+e^{-}\nb) mn^{4+}→mn^{7+}+3e^{-}\nc) mn^{4+}+e^{-}→mn^{3+}\nd) mn^{4+}+3e^{-}→mn^{7+}

which half - reaction correctly represents reduction?\na) mn^{4+}→mn^{3+}+e^{-}\nb) mn^{4+}→mn^{7+}+3e^{-}\nc) mn^{4+}+e^{-}→mn^{3+}\nd) mn^{4+}+3e^{-}→mn^{7+}

Answer

Brief Explanations:

Reduction is a gain of electrons. In a reduction half - reaction, the oxidation state of the species decreases as it gains electrons. In option C, $Mn^{4 + }$ gains an electron ($e^-$) and its oxidation state decreases from +4 to +3. In option A, it is an oxidation half - reaction as electrons are lost. In option B, electrons are lost and the oxidation state increases. In option D, the oxidation state increases while gaining electrons which is not possible.

Answer:

C. $Mn^{4+}+e^-\rightarrow Mn^{3+}$