a. what is the hybridization of the central atom in xef₄? hybridization = what are the approximate bond…

Explanation:

Step1: Determine valence - electron number of central atom in XeF₄

Xe has 8 valence electrons, and each F contributes 1 bonding electron. The number of electron - pair groups around Xe is $\frac{8 + 4}{2}=6$ (4 bonding pairs and 2 lone pairs).

Step2: Identify hybridization of Xe in XeF₄

Based on the number of electron - pair groups, the hybridization is $sp^{3}d^{2}$.

Step3: Determine bond angles in XeF₄

The molecular geometry of XeF₄ is square planar. The bond angles are 90° and 180°.

Step4: Determine valence - electron number of central atom in BrF₃

Br has 7 valence electrons, and each F contributes 1 bonding electron. The number of electron - pair groups around Br is $\frac{7+3}{2}=5$ (3 bonding pairs and 2 lone pairs).

Step5: Identify hybridization of Br in BrF₃

Based on the number of electron - pair groups, the hybridization is $sp^{3}d$.

Step6: Determine bond angles in BrF₃

The molecular geometry of BrF₃ is T - shaped. The bond angles are approximately 90°.

Answer:

A. Hybridization = $sp^{3}d^{2}$, Bond angles = 90° and 180° B. Hybridization = $sp^{3}d$, Bond angles = 90°