hydrogen gas combines with oxygen gas to produce dihydrogen monoxide. 1 point how many moles of dihydrogen…

hydrogen gas combines with oxygen gas to produce dihydrogen monoxide. 1 point how many moles of dihydrogen monoxide will be formed from 2.14 moles of hydrogen gas\n4.28 moles\n6.33 moles\n1.07 moles\n2.14 moles\nclear selection\nhydrogen gas combines with oxygen gas to produce dihydrogen monoxide. 1 point how many moles of dihydrogen monoxide will be formed from 2.14 moles of of oxygen gas?\n1.07 moles\n6.33 moles\n2.14 moles\n4.28 moles\nclear selection

hydrogen gas combines with oxygen gas to produce dihydrogen monoxide. 1 point how many moles of dihydrogen monoxide will be formed from 2.14 moles of hydrogen gas\n4.28 moles\n6.33 moles\n1.07 moles\n2.14 moles\nclear selection\nhydrogen gas combines with oxygen gas to produce dihydrogen monoxide. 1 point how many moles of dihydrogen monoxide will be formed from 2.14 moles of of oxygen gas?\n1.07 moles\n6.33 moles\n2.14 moles\n4.28 moles\nclear selection

Answer

Explanation:

Step1: Write the balanced chemical equation

$2H_2 + O_2=2H_2O$ (dihydrogen monoxide is water). The mole - ratio of $H_2$ to $H_2O$ is 1:1, and the mole - ratio of $O_2$ to $H_2O$ is 1:2.

Step2: Calculate moles of $H_2O$ from $H_2$

Given 2.14 moles of $H_2$. Since the mole - ratio of $H_2$ to $H_2O$ is 1:1, the moles of $H_2O$ formed is also 2.14 moles.

Step3: Calculate moles of $H_2O$ from $O_2$

Given 2.14 moles of $O_2$. Since the mole - ratio of $O_2$ to $H_2O$ is 1:2, the moles of $H_2O$ formed is $2.14\times2 = 4.28$ moles.

Answer:

For the first question: 2.14 moles For the second question: 4.28 moles