hydrogen gas can be produced by the reaction of magnesium metal with hydrochloric acid by the reaction…

hydrogen gas can be produced by the reaction of magnesium metal with hydrochloric acid by the reaction below. mg + 2hcl → mgcl₂ + h₂ if 4.00 g of mg is reacted with 3.20 g of hcl, what is the limiting reactant? o mg o hcl done

hydrogen gas can be produced by the reaction of magnesium metal with hydrochloric acid by the reaction below. mg + 2hcl → mgcl₂ + h₂ if 4.00 g of mg is reacted with 3.20 g of hcl, what is the limiting reactant? o mg o hcl done

Answer

Explanation:

Step1: Calculate moles of Mg

Molar mass of Mg is 24.31 g/mol. Moles of Mg = $\frac{4.00\ g}{24.31\ g/mol}$ $\approx$ 0.165 mol.

Step2: Calculate moles of HCl

Molar mass of HCl is 36.46 g/mol. Moles of HCl = $\frac{3.20\ g}{36.46\ g/mol}$ $\approx$ 0.088 mol.

Step3: Determine mole - ratio from the balanced equation

From the equation Mg + 2HCl → MgCl₂ + H₂, the mole - ratio of Mg to HCl is 1:2.

Step4: Calculate moles of HCl required to react with Mg

If all 0.165 mol of Mg reacts, moles of HCl required = 2×0.165 mol = 0.33 mol. But we have only 0.088 mol of HCl.

Step5: Identify the limiting reactant

Since we don't have enough HCl to react with all of the Mg, HCl is the limiting reactant.

Answer:

HCl