hydrolysis of salts and reactions of acids and bases\ndescribe each as an acid, base, neutral salt, acidic…

hydrolysis of salts and reactions of acids and bases\ndescribe each as an acid, base, neutral salt, acidic salt, or basic salt. for each salt write a dissociation equation, and hydrolysis equation (only for acidic and basic salts). for acids and bases write an equation to show how each reacts with water.\n1. nh₃\n2. kcl\n3. hno₃\n4. nahco₃\n5. rboh\n6. alcl₃\n7. h₂c₂o₄\n8. nac₆h₅o\n9. na₂co₃

hydrolysis of salts and reactions of acids and bases\ndescribe each as an acid, base, neutral salt, acidic salt, or basic salt. for each salt write a dissociation equation, and hydrolysis equation (only for acidic and basic salts). for acids and bases write an equation to show how each reacts with water.\n1. nh₃\n2. kcl\n3. hno₃\n4. nahco₃\n5. rboh\n6. alcl₃\n7. h₂c₂o₄\n8. nac₆h₅o\n9. na₂co₃

Answer

Explanation:

Step1: Identify NH₃

NH₃ is a base. Reaction with water: $NH_{3}+H_{2}O\rightleftharpoons NH_{4}^{+}+OH^{-}$

Step2: Identify KCl

KCl is a neutral salt. Dissociation: $KCl = K^{+}+Cl^{-}$, no hydrolysis as it's from strong - acid (HCl) and strong - base (KOH).

Step3: Identify HNO₃

HNO₃ is an acid. Reaction with water: $HNO_{3}+H_{2}O=H_{3}O^{+}+NO_{3}^{-}$

Step4: Identify NaHCO₃

NaHCO₃ is a basic salt. Dissociation: $NaHCO_{3}=Na^{+}+HCO_{3}^{-}$. Hydrolysis: $HCO_{3}^{-}+H_{2}O\rightleftharpoons H_{2}CO_{3}+OH^{-}$

Step5: Identify RbOH

RbOH is a base. Dissociation: $RbOH = Rb^{+}+OH^{-}$

Step6: Identify AlCl₃

AlCl₃ is an acidic salt. Dissociation: $AlCl_{3}=Al^{3 + }+3Cl^{-}$. Hydrolysis: $Al^{3+}+3H_{2}O\rightleftharpoons Al(OH)_{3}+3H^{+}$

Step7: Identify H₂C₂O₄

H₂C₂O₄ is an acid. First - step dissociation: $H_{2}C_{2}O_{4}+H_{2}O\rightleftharpoons H_{3}O^{+}+HC_{2}O_{4}^{-}$

Step8: Identify NaC₆H₅O

NaC₆H₅O is a basic salt. Dissociation: $NaC_{6}H_{5}O=Na^{+}+C_{6}H_{5}O^{-}$. Hydrolysis: $C_{6}H_{5}O^{-}+H_{2}O\rightleftharpoons C_{6}H_{5}OH + OH^{-}$

Step9: Identify Na₂CO₃

Na₂CO₃ is a basic salt. Dissociation: $Na_{2}CO_{3}=2Na^{+}+CO_{3}^{2 - }$. Hydrolysis: $CO_{3}^{2-}+H_{2}O\rightleftharpoons HCO_{3}^{-}+OH^{-}$

Answer:

  1. Base, $NH_{3}+H_{2}O\rightleftharpoons NH_{4}^{+}+OH^{-}$
  2. Neutral salt, $KCl = K^{+}+Cl^{-}$, no hydrolysis
  3. Acid, $HNO_{3}+H_{2}O=H_{3}O^{+}+NO_{3}^{-}$
  4. Basic salt, $NaHCO_{3}=Na^{+}+HCO_{3}^{-}$, $HCO_{3}^{-}+H_{2}O\rightleftharpoons H_{2}CO_{3}+OH^{-}$
  5. Base, $RbOH = Rb^{+}+OH^{-}$
  6. Acidic salt, $AlCl_{3}=Al^{3 + }+3Cl^{-}$, $Al^{3+}+3H_{2}O\rightleftharpoons Al(OH)_{3}+3H^{+}$
  7. Acid, $H_{2}C_{2}O_{4}+H_{2}O\rightleftharpoons H_{3}O^{+}+HC_{2}O_{4}^{-}$
  8. Basic salt, $NaC_{6}H_{5}O=Na^{+}+C_{6}H_{5}O^{-}$, $C_{6}H_{5}O^{-}+H_{2}O\rightleftharpoons C_{6}H_{5}OH + OH^{-}$
  9. Basic salt, $Na_{2}CO_{3}=2Na^{+}+CO_{3}^{2 - }$, $CO_{3}^{2-}+H_{2}O\rightleftharpoons HCO_{3}^{-}+OH^{-}$