interpreting the question\nunknown\nthe overall question is:\nbr₂ + 2nai → i₂ + 2nabr\nhow many moles of i₂…

interpreting the question\nunknown\nthe overall question is:\nbr₂ + 2nai → i₂ + 2nabr\nhow many moles of i₂ form when 5.0 mol nai react with bromine according to the reaction above?\nwhat is the unknown in the question?\nmol i₂\nmol nai\n5.0 mol nai

interpreting the question\nunknown\nthe overall question is:\nbr₂ + 2nai → i₂ + 2nabr\nhow many moles of i₂ form when 5.0 mol nai react with bromine according to the reaction above?\nwhat is the unknown in the question?\nmol i₂\nmol nai\n5.0 mol nai

Answer

Explanation:

Step1: Identify mole - ratio

From the balanced chemical equation $Br_2 + 2NaI\rightarrow I_2+2NaBr$, the mole - ratio of $NaI$ to $I_2$ is $2:1$.

Step2: Set up proportion

Let $x$ be the number of moles of $I_2$. We know that $\frac{\text{moles of }NaI}{\text{moles of }I_2}=\frac{2}{1}$. Given that the moles of $NaI = 5.0$ mol. So, $\frac{5.0}{x}=\frac{2}{1}$.

Step3: Solve for $x$

Cross - multiply: $2x = 5.0\times1$. Then $x=\frac{5.0}{2}=2.5$ mol.

Answer:

2.5 mol $I_2$